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Require the diameter of a pully
to make 116.3 revolutions a minute
the drum fixed on the shaft being
18 inches diameter making 96.923
revolutions a minute.

96.923 revolutions of shaft a min
18 inches diameter of drum
-----
775384
96923
-----
revolution [reqd?] 116.3) 1744614 (15 in diameter

- - - - - - - - - - - -
Problem. First shaft 96 revolutions a minute
drum on said shaft 18 in diam
drum on second shaft 14 in diam
drum on second shaft for driving
the third shaft 10 inches diameter
drum on third shaft 9 inches diam
Drum on 2nd shaft 14 inches diameter
Drum on 3rd shaft 9 " "
-----
126 [?]

96 revolutions of shaft a minute
18 inches diameter of drum on this shaft
-----
768
96
-----
1728
10
-----
126) 17280 (137.14 revolutions of counter
shaft a minute

Rules and examples for changing
light gearing to heavy or heavy
gearing to light

Rule
Reduce the wheels to there lowest
terms, by directing them by any
number without a remainder
then multiply the lowest terms
of the wheels by any one number
that will produce the number
of teeth required

Thus
(2) 48
-----
lowest term 4
(3) 36
-----
3 lowest term
lowest term 4 lowest term 3
wheel 2/8 teeth and 2/6 teeth
lowest term 4 lowest term 3
wheel 3/12 teeth and 3/9 teeth

Notes and Questions

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