9
Facsimile
Transcription
Status: Needs Review
Compare two signals in the same magnetic field:
signal height recorded by the milliammeter
= C[j(j+1)γ^4 / (width)^2] (Molarity) (percent Abundance)
For Cd μCd = 0.65 j=1/2 NaCl 5.5 M
Na μNa = 2.215 j=3/2 CdCl2 2 [M]
(Signal/noise) ratio for Na observed in scope ~ [1₀?]
(Signal/noise) ratio for Cd recorded in meter
~0.0565 x 200 = 11.3
assuming 200 times enhanced.
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