Research Notes III, 1950

Oct. 14, '50 Determination of the spin value of Be9

Beryllium was precipitated not as Be(OH)2 from the water solution of unknown amount of Be(NO3)2 by NH4OH. The precipate was thoroughly washed with water and droed in an over to constant weight. 1.098 gram of dried Be(OH)2 was dissolved in 6 N. nitric acid to form a neutral Be(NO3)2 solution of 10 [cic?]. The molarity of the solution Be(NO3)2 = 2055.

Oct 17, '50

A resonance was discovered in the water solution of Ta₂O₅ + 48% HF at a field H₀ = 9500 G & frequency 5.502 Mc.

Oct. 19, '50

Both presumable Pd¹⁰⁵ & Ta¹⁸¹ resonance came from water. Using triply-distilled H₂O & 99.5% D₂O, we obtained the same resonance as shown on the tape. CCl₄ did not give a signal.

Oct. 20, '50

wt. of beaker = 58.160 g. wt. of beaker = 58.580 +D₂O --------------------------------- wt. of D₂O = 0.420 g. diluted to 100 cc. with H₂O in which 4.95 g. of MnCl₂ · 4 H₂O was added.

Molarity of D = 0.44 " " Mn = 0.25

Pd¹⁰⁵ search records

ν = 7.50 Mc H₀ ~ 9000 4640 G - 5250 G μ: 1.065 (2I) --> 0.940 (2I) μ_N

ν = 6.65 Mc H₀ ~ 4640 - 5230 G μ: 0.940⁺ (2I) --> 0.836 (2I) μ_N

ν = 5.90 Mc H₀ ~ 4590 - 5220 G μ: 0.846 (2I) --> 0.743 (2I) μ_N

ν = 5.20 Mc H₀ ~ 4590 - 5230 G μ: 0.746 (2I) --> 0.655 (2I) μ_N

ν = [6?].70 Mc μ: 0.660 (2I) --> 0.569 580 (2I) μ_N H₀ = 6680 --> 7750 G

ν = 5.80 90 Mc H₀ ~ 6680 --> 7600 G μ: 0.570 0.584 --> 0.514 H₀ ~ 6680 --> 7550 G μ: 0.584 (2I) --> 0.515 (2I)

ν = 7.10 Mc H₀ = 9000 --> μ:

Nov. 4, 1950

Calibration of sweep field

1	2H₃	2.6 G
1/2	-	1.07
3\10	-	0.60
1\5	-	0.39
1\10	-	0.17

Calibration of R.F. field

No. of cells	Veff	H₁
1/2	0.05 v.	0.022 Gauss
1	0.12	0.053
1 1/2	0.20	0.089
2	0.30	0.134
2 1/2	0.39	0.174
3	0.49	0.218
3 1/2	0.60	0.268
4	0.71	0.316

Each cell has approx 40 v.

Saturation experiment of O¹⁷ resonance in H₂O + 0.025 M Fe(NO₃)₃ H_s = 0.085 G

True width =

No. of cells	signal amplitude
1\2	9.4 ± 1.2
1	17.5 ± 2.5
1 1\2	18.8 ± 1.1
2	17.8 ± 2.0
2 1\2	13.4 ± 1.5
3	11.0 ± 2.5

Assume H₁ = 0.1 G at saturation

[the following table is crossed out]

H₁ =				H.f x 100
0.02	1.02	0.294	0.156	0.31	.19 .212
0.04	1.08	0.278	0.152	0.61	.32 .50
0.06	1.17	0.256	0.142	0.85	0.287 .95
0.08	1.28	0.234	0.130	1.04	.288 1.67
0.10	1.42	0.211	0.118	1.18	.197 2.89
0.12	1.56	0.192	0.106	1.27	.179
0.14	1.72	0.174	0.096	1.34	.162
0.16	1.89	0.159	0.088	1.41	--
0.18	2.06	0.145	0.082	1.47	--
0.20	2.24	0.134	0.074	1.48	--
0.22	2.42	0.124	0.067	1.47	--
0.24	2.60	0.115	0.060	1.44	--