Fu Chun Yu Lab Notebooks

Oct. 12, '50

Frequency of Pd¹⁰⁵ in H₂PdCl₄ compound with that of Cl³⁵ in HCl.

H₀ = 10830 G

[Break]

Pd¹⁰⁵ (6240 --> 6230 KC) in H₂PdCl₆

Time	Distance bet Markers	Marker	Resonance Distance	Resonance frequency	Δν	Δν²
3 min	24.8 mm	#1	14.1 mm	6234.4 KC	0.1	0.01
64	43.5	"	25.4	6234.3	0.2	0.04
102	43.0	"	24.1	6234.5	0.0	0.0
134	44.2	#.2 1	19.8 24.4	6234.6	0.1	0.01
166	43.5	"	23.1	6234.8	0.3	0.09

Cl³⁵ (4510 --> 4500 KC) in HCl

50 min	52.8 mm	31	22.9 mm	4505.8 KC	0.3	0.09
86	52.8	"	20.8	4506.2	0.1	0.01
118	52.7	"	20.8	4506.2	0.1	0.01
181	54.2	"	21.3	4506.2	0.1	0.01

{{tex: $\overline{\Delta\nu^2} = 0.04$ :tex}}

Actually the resonance is due to O¹⁷ in H₂O

Oct 17, '50

A resonance was discovered in the water solution of Ta₂O₅ + 48% HF at a field H₀ = 9500 G & frequency 5.502 Mc.

Oct. 19, '50

Both presumable Pd¹⁰⁵ & Ta¹⁸¹ resonance came from water. Using triply-distilled H₂O & 99.5% D₂O, we obtained the same resonance as shown on the tape. CCl₄ did not give a signal.

Oct. 20, '50

wt. of beaker = 58.160 g. wt. of beaker = 58.580 +D₂O --------------------------------- wt. of D₂O = 0.420 g. diluted to 100 cc. with H₂O in which 4.95 g. of MnCl₂ · 4 H₂O was added.

Molarity of D = 0.44 " " Mn = 0.25

Pd¹⁰⁵ search records

ν = 7.50 Mc H₀ ~ 9000 4640 G - 5250 G μ: 1.065 (2I) --> 0.940 (2I) μ_N

ν = 6.65 Mc H₀ ~ 4640 - 5230 G μ: 0.940⁺ (2I) --> 0.836 (2I) μ_N

ν = 5.90 Mc H₀ ~ 4590 - 5220 G μ: 0.846 (2I) --> 0.743 (2I) μ_N

ν = 5.20 Mc H₀ ~ 4590 - 5230 G μ: 0.746 (2I) --> 0.655 (2I) μ_N

ν = [6?].70 Mc μ: 0.660 (2I) --> 0.569 580 (2I) μ_N H₀ = 6680 --> 7750 G

ν = 5.80 90 Mc H₀ ~ 6680 --> 7600 G μ: 0.570 0.584 --> 0.514 H₀ ~ 6680 --> 7550 G μ: 0.584 (2I) --> 0.515 (2I)

ν = 7.10 Mc H₀ = 9000 --> μ:

Nov. 4, 1950

Calibration of sweep field

1	2H₃	2.6 G
1/2	-	1.07
3\10	-	0.60
1\5	-	0.39
1\10	-	0.17

Calibration of R.F. field

No. of cells	Veff	H₁
1/2	0.05 v.	0.022 Gauss
1	0.12	0.053
1 1/2	0.20	0.089
2	0.30	0.134
2 1/2	0.39	0.174
3	0.49	0.218
3 1/2	0.60	0.268
4	0.71	0.316

Each cell has approx 40 v.

Saturation experiment of O¹⁷ resonance in H₂O + 0.025 M Fe(NO₃)₃ H_s = 0.085 G

True width =

No. of cells	signal amplitude
1\2	9.4 ± 1.2
1	17.5 ± 2.5
1 1\2	18.8 ± 1.1
2	17.8 ± 2.0
2 1\2	13.4 ± 1.5
3	11.0 ± 2.5

Assume H₁ = 0.1 G at saturation

[the following table is crossed out]

H₁ =				H.f x 100
0.02	1.02	0.294	0.156	0.31	.19 .212
0.04	1.08	0.278	0.152	0.61	.32 .50
0.06	1.17	0.256	0.142	0.85	0.287 .95
0.08	1.28	0.234	0.130	1.04	.288 1.67
0.10	1.42	0.211	0.118	1.18	.197 2.89
0.12	1.56	0.192	0.106	1.27	.179
0.14	1.72	0.174	0.096	1.34	.162
0.16	1.89	0.159	0.088	1.41	--
0.18	2.06	0.145	0.082	1.47	--
0.20	2.24	0.134	0.074	1.48	--
0.22	2.42	0.124	0.067	1.47	--
0.24	2.60	0.115	0.060	1.44	--

1+x2	x	.99	(1+x)3/2	normalized
1.04	0.2	0.195 0.189	1.06	3.7 9.75 9.3
	0.3	0.263	1.25	6.1 15.9 15.7
1.16	0.4	0.320	1.58	18.9 18.7
1.36	0.6	0.380
	0.707	0.386	2.09	19 19.0
1.64	0.8	0.381
2.00	1.0	0.356	2.81	17.7 18.8
2.44	1.2	0.316	3.80	15.7 17.5
2.96	1.4	0.275	5.08	13.7 15.6
3.56	1.6	0.238	6.70	11.9 13.5
4.24	1.8	0.208	8.66	10.1 10.2
5.00	2.0	0.180	11.10	9.05 8.9

γ2T1T2H12 = 0.64 0.50	H1=0.09 G	γT1 = 0.50/γT2
γ2T1T2 = 0.64/0.01 = 64 0.50/0.89 =	γT1/γT2 = 0.50 (W/H)² = 0.50(0.2/0.09)² x 3 = 6

x = 8H₁ [note above 8: 7.85]

	x	x	H1
H1 = 0.02	0.16	0.2	0.016 0.0255
0.04	0.32	0.4	0.05 0.051
0.06	0.48	0.6	0.0715 0.0765
0.08	0.64	0.8	0.10 0.0274 0.102
0.1	0.80	1.0	0.125 0.1591 0.1274
0.12	0.96	1.2	0.15 0.153
0.14	1.12	1.4	0.175 0.1783
0.16	1.28	1.6	0.20 [0.255] 0.204
0.18	1.44	1.8	0.225 0.229
0.20	1.60	2.0	0.255

Saturation experiement on D² resonance in 0.56 M D in 3.9 M Mn Cl₂ H_s = 0.085 G

No. of cells	Signal amplitude
1/2	22.2 ± 2.8
1	49.7 ± 0.5
1 1/2	69.4 ± 6.7
2	91.8 ± 4.0
2 1/2	88.5 ± 6.3
3	81.6 ± 0.6
3 1/2	75. 8 ± 3.6
4	62.2 ± 3.8

Max occurs at H₁=0.15 G

x	H₁	dv/dH
0.2	0.043	67.5
0.4	0.085	114.3
0.6	0.127	136
0.8	0.170	136
1.0	0.223	127
1.2	0.256	113
1.4	0.298	98
1.6	0.340	85

11/9/50 -- γT₂H₁ υ = ---------------------------------- M₀ 1+(T₂∆w)²+γ²H₁²T₁T₂

dυ dυ 2γ²T₂³H₁∆w ----- = ----- ⋅ γ = ------------------------------------ M₀ dH₂ d(∆w) [1+γ²H₁²T₁T₂ + (T₂∆w²)]²

dυ 3√3 γ²T₂²H₁ ( ----- ) = ----- ----------------------------- M₀ dH max 8 [1+γ²H₁²T₁T₂]³/²

1 1 a + ∆w = ---- ---- √(1+γ²H₁²T₁T₂) √3 T₂

dυ 3√3 H₁Hₛ 1 SIGNAL RECORDED = Hₛ ( ----- ) = ----- M₀ ------------- ------------------------ dH max 2 (width)² √(1+γ²H₁²T₁T₂)

M₀ ~ n γ w²₀ 1 H₁Hₛ ~ I(It₁) n γ w²₀ ----------------------- -------- √(1+γ²H₁²T₁T₂) (width)²

Comparing two signal at same w₀ 8Hₛ width = ∆H

Iₐ(Iₐ+1)nₐγₐH₁ₐ √(1+γ²H₁²T₁T₂) -------------------- ---------------------- ( ---------

11/9/50 The magnitutde & width of 0 (SUPERSCRIPT) 17 resonance & of O (SUPERSCRIPT)2 resonance was measured at the same fielf with the results:

O(SUPERSCRIPT) 17 H= 26.8 +_ 1.9 W = 17.2 +_ 2.6 mm H(SUB)1 = 0.089

Rate 664 mm/10KC

D(SUPERSCRIPT)2 H= 35.0 +_ 1.9 W= 22.3 +_3.0 mm H(SUB)1 = 0.022

573.5 mm/10KC 22% Ratio of w(SUPERSCIPT)2 H= 0.455

I + 2.8 +_ 0.43 I (IH) + 10.8 +_ 2.4

(Stricken out): Corrected for he different rate at 5.80 & 660 Mc I (I+1) = (35.6 +_ 7.9)/4 I = 2.53+_

(Back to Normal text) Corrected for the different rate at 5.80 Mc & 6.67 Mc I (I+1) = 10.36 +_ 2.3 I = 2.76 +- 0.36

11/13/50

The magnitude & width of O¹⁷ resonance & of H resonance was measured at different field & frequency with the results:

O17	Height = 29.3 ± 2.3	H1 = 0.089 G	.0253 G/mm
Rate 1373 mm/20 KC	w = 14.5 ± 2.0 mm	w = 0.366 G
H1	Height = 18.9 ± 0.76		.0322 G/mm
attenuated to 1/500 Rate 292.5 mm/40 KC	w = 14.4 ± 0.75	w = 0.464 G