Fu Chun Yu Lab Notebooks

[Greek letter mu] CdA = 0.623 + 0.001 [Greek letter mu] CdB = 0.595 + 0.001

[Greek letter mu] CdA = 1.0461 + 0.0001 [Greek letter mu] CdB

The sign of the magnetic moments of Cd isotopes was compared with that of iodine & sodium. It showed that Cd isotopes have negative magnetic moments

August 15, '49 We have added 15 band pairs. _R_ R = 1.5M = C C = 10.0 [mu]fd _R_

A noise improvement change of [square root] 34.7/4.76 = 2.70 The figure was [square root] 5000/2[times]1/2[pi]x4.76 = 305

Ohm per cm cube of tin at 20°C = 11.5 x 10^-6 = ρ

ε = [skin?] depth in cm =

f in cycles

Fw tin

August 24, 1949

Resonance Frequencies [double underline] Sn^115 (6250 -> 6225 KC)

Time	Marker Dist.	Res. Dist.	Marker	Res. Frequency	[fancy]v - [average]v = [Greek letter delta]v	([delta]v)^2

9	69.8	38.7	1	6236.2 KC	-0.2	0.04
60	69.0	37.0	1	6236.7	+0.3	0.09
106	69.6	37.4	2[crossed out] 1	6236.7	+0.3	0.09
328	69.0	38.2	1	6236.3	-0.1	0.01
378	69.1	39.0	1	6236.0	-0.4	0.16
432	70.0	41.0	[illegible]	Av + 6236.4 KC ([fancy][average]v) + 0.3		[square root of the average]([delta]v)^2 = 0.3

[the last row of data (not calculations) is crossed out]

Na^23 (5050 -> 5025)

Time	Marker Dist.	Res. Dist.	Marker	Res. Frequency	[fancy]v - [average]v = [Greek letter delta]v	([delta]v)^2

27	116.0	24.0	1	5044.9	+0.3	0.09
75	114.9	24.0	2	5044.7	+0.1	0.01
161	115.4	25.5	1	5044.6	0.0	0
343	115.0	25.1	2	5044.5	-0.1	0.01
396	115.0	25.1	2	5044.5	-0.1	0.01
				[fancy][average]v) = 5044.6 KC + 0.2		[square root of the average]([delta]v)^2 = 0.2

V ( Sn 115 ) = 6236.4 ( 1 + 5X10-5 )

V ( Na 23 ) = 5044.6 ( 1+ 4X10-5 )

V ( Sn 115 ) = 6236.4 ( 1+ 6.2 x 10-5 ) V ( Na 23 ) = 5044.6

= 1.23625 ( 1+ 6.2 x10 -5 ) = 1.23625 (1+0.00006 ) = 1.23625 + 0.000076

Data obtained by WP

V (Sn 119 ) = 1.4090 + 0.0005 V ( Na 23 )

V ( Sn 117 ) = 1.3464 + 0.0004 V ( Na 23 )

V ( Sn 119 ) = 1.0465 + 0.0003 V ( Sn 119 )

M ( Sn 117 ) = - 1.0000 + 0.0009 MN M (Sn 119 ) = - 1.0466 + 0.0009 MN

Therefore

August 24, 1949. A search coil was made In studing the shillding effect of metallic to filing which were coated with SnO [?????????} by working with ver dilute HNo3

Measured the search coil in Q-meter

C1 reasonance freq.

30 mmt 25.5 MC 6. 18.5 MC 10 [-----?] of [enanieded?] wires of 5 mm dia.

L ( C+C1 ) = 1/4 tt 2 f2 L ( C + 30 ) = 3.9 x 10-5 L ( C + 60 ) = 7.4 x 10-5

C+60 7.4 = 1.9 C+ 30 3.9 = "

C + 60 = 1.9c+ 57 0.9c= 3 C=10/3= 3.33mmf L= 1.17 [???]

RMS (a) ------ empty tube induced netage = 0.012v To vaccum tube volhuster (b) -------- filed this filmigs, RMS induced voltage = 0.011v

(c) ---- coil surrounded by a small copper of about 0.2mm Hosh induced netage = 0 Conclusion Nethough the the zie of this filnig in large the shielding effect is very small Bloch: Perhaps the tin filing were over oxidized that we were working with the oxide rather than tin metal. Experiments must be repeated with tin metal. 8/26/49 repeated with metallic tin. No shielding effect.

Comparison of resonances of [] tin isotopes at the same frequency

August 25, 1949.

Non-linearity in the Freq. Measurement

ν frequency

x line in recording milliammeter

Measure rate in units of KC/line (= dν/dx)

Assume the rate vary linearly (not uniformly) with frequency in an interval of 25 KC.

ν₀ = [?] freq.

ν₁ = final "

where a(ν₀ = rate at frequency ν₀

per line

Integration of (1) gives

August 26, '49

Fine tin powder was made from CP tin by filing. Total amount = 7.5 gms in 3 cc. Density = 2.5 gms/cc

A search coil was immersed in this tin powder. No reduction of radio signal by comparison of the output with that by without tin powder. No shielding effect was observable.

Sample Sb #4

Dissolve 21 gms of SbCl₃ into 12 c.c of warm soln. Stand for a few days. Pour the 7 cc clear soln into a test tube & add two c.c of conc. HCl. The precipitate rejected. Contains min SbCl₃ 1 gm/c.c. ~ 5 Molar of Sb

August 27, 1949 Sb #5 15 gms of SbCl₃ in 3 cc. conc. HCl makes a 8 c.c. soln Molarity ~8 M

August 28, 1949 Size & Sign Comparison (Tin)

Sizes of resonance lines of Sn¹¹⁹, Sn¹¹⁷, Sn¹¹⁵ compared at the same frequences 7.14 MC

Na Res.	Sn119
5.06	7.14 MC (119 res)	(9.8%)
5.30	7.14 (117 res)	(9.1%)
5.77	7.14 (115 res)	0.4 %

-------------------------

γ² (Sn¹¹⁹) : γ²(Sn¹¹⁷) : γ²(Sn¹¹⁵) = 1.096 : 1.00 : 0.843

Abundance Sn¹¹⁹ : Sn¹¹⁷ : Sn¹¹⁵ = 9.8 : 9.1 : 0.4

Product of abundance & γ² = 1.075 : 0.91 : 0.0337 = 1.00 : 0.846 : 0.0314 100 : 84.6 : 3.1