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Weaving

If the crank shaft of a power loom makes 119.441 revo-lutions a minute .i.e so many picks or threads what length time must it work succes-sively to produce a piece of [cloth?] 29 yards long with 84 pick or threads in 1 inch

29 yds long 37 in [h???d] / yd ----- 203 87 ----- 1073 84 picks / in ----- 429 2 119.441) 90132.0 (754 8584 ----- 90132 dividend

minuts / hour 60) 754.615 -----12.34

h m sec Ans 12-34-36 .615 60 seconds/ ----- 36,900

(Twist) (Warp) (Weft) [?]

Or

When the Warp and filling are the same it may be worked in one operation by [multipleing?] the count of reed by the pricks in 1 inch and the length of the piece and the inches width at the reed for a dividend. Then multiply the number of hanks in 1 yard by the number of yarn for a divisior and the product will be the answer

Last edit 10 months ago by cowbot
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The weight of yarn is required in the following manner

Rule

Multiply the length of the piece required by the count of the reed and the product by the wedth at the reed for a dividind for the warp dividind 840 yds 1 hank divisor

Then Multiply the length of the piece by the picks 1 inch then by the inches wide at the reed for a dividend for filling andivid by the number of yds in one hank then add the two products together and divide by the number of yarn and the decimals by the [or?] lb

[illegible] Weaving

The weight of yarn is required to make one piece of cloth of the following descriptor

length of piece 29yds count of reed 72 Manches No of twist 36s Wedths of warp at reed 29 1/2 inch No of picks in 88 No weft 36s

29 length of piece 72 count of reed ----- 58 203 ----- 2088 29[?] inch wid at reed ----- 18792 4176 1044 ----- 1 hank is 840 yd) 61590 (73.328 hawks twist

29 yds length 88 threads in 1 inch ----- 232 232 ----- 2552 29.5 29 1/2 inch [undeatred?] ----- 12760 22968 5104 ----- [yds?] hawk 840) 752840 (89.624 hawks weft reqd

Ans 4 bs 8 1/2 oz nearly

[left-hand margin] No. [yds?] [10.32?] 89.624 ----- 36) 162.952 ----- 4.526 16 oz lb ----- 3156 526 8.416 4 yds [illegible] ----- 1.664

Last edit 10 months ago by madeleinemurphy6
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Weaving

If a warp 146 yds long 39 inches wide at the reed and 106 ends in an inch weigh 12lbs what number of twist will it be

146 yards length of warp 39 width of warp at reed ----- 1314 438 ----- 5694 106 Ends in an inch ----- 34164 5[?]940 ----- weight of warp 12) 603564 No of yards in warp ----- 50297

1 hank in 840 yds) 50297 (59.87 4200 ----- 8297 7560 ----- 7370 6720 ----- 6500 5880 ----- 620

Weaving

What length and weight of No 60[s] twist will it require for a piece of cloth 29 1/5 yds long 39 inch wide at the reed 106 ends in an inch

292 yds length of piece 39 inches wide at the reed ----- 2628 876 ----- 11388 106 ends in an inch ----- 68328 113880 ----- 120712.8 yds of twist required dividind

yds hawk 840 60s twist ----- Divisor 50400 yds in 1 lb of No 60s twist

50400) 120712.8 (2lb 6 1/4 oz 100800 ----- 19912.8 16 oz lb ----- 1194768 199128 ----- 578604.8 (6 302400 ----- 16204.8 4 [illegible] 1 oz ----- 64819.2 (1 50400 ----- 14419

Ans 2 lb, 6 1/4 oz 29 yds in [pick?] ll lb, 15 1/4oz for 5 pieces

Last edit 10 months ago by madeleinemurphy6
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Weaving What weight of number 80 [?] Weft (or filling) will it require to weave a piece of cloth 29 1/5 yards long 120 picks in an inch 39 inch wide at the reed allow 1-50 for waste

yds [hark?] 840 weft [8?] 80 [?] 67200

29.2 length of piece 120 pks in [inch?] 5840 292 3504,0 39 inch wid at reed 315360 105120 waste 1,50 136656,0 2733,12 [ff?] or 67200 39389,1 421, 1/3 [50? 13?] 34400 4989.12 16 oz lb 2993472 498912 79825.92 1 67200 12625 = 1/5 Ans 2^lbs 1 1/3 oz

Speed If a drum 42 1/4 inches diameter, drives the beaters of a flowing machine 1344 revolutions per minute what must the diameter of a drum be for the beaters to make 1560 revolutions; and if the present drum is to be laged what thickness must the lags be

1344 : 42.25 :: 1560 1560 253500 21125 4225 1344 65910.00 49,04 diam required 5376 12150 12096 5400 5376 24

49,04 diameter required 42,25 diameter of given drum 2 6,79 difference of diameters ^of drums 3,395 or 3, 1/4 in lag required

Last edit about 1 year ago by lmoore
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Speed

If a drum 42 1/4 inches deameter drives the beater of a [blowing?] machine 1344 revolutions per What number of revolutions per minute will the beater of make if driven from a drum 49 1/25 inches diameter 42 1/4 or 42-25: 1344: [:49.04?] or 43 1/25 1344 49.04 5376 120960 5376 4225 [sqrt?] 65909.76 1560 revolutions of beater a minute nearly

Speed If a [pully?] 13 inches diameter drives the main cylindar of a [carding?] engine at the rate of 126 revolutions a minute what diameter must a pully be, to reduce the speed of the cylindar to 112 revolutions

126 revolutions given 13 376 inches diameter of given pully revolutions required 126 112 [sqrt?] 163 14.625 or 14 5/8 inches diameter of pully required 112 518 448 700 672 280 224 560 560

Last edit 25 days ago by LunaVasquez
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